Question

A liquid of mass m and specific heat c is heated to a temperature 2T. Another liquid of mass m/2 and specific heat 2 c is heated to a temperature T. If these two liquids are mixed, the resulting temperature of the mixture is
A. (2/3) T
B. (8/5)T
C. (3/5)T
D. `(3/2)`T

Answer 1

Correct Answer - D
Temperature of mixture,
`theta(mix) = ((m_(1)c_(1)T_(1)+ m_(2)c_(2)T_(2))/(m_(1)c_(1)+ m_(2)c_(2))` = `(m xx cxx 2T+(m/2)(2c)T)/(mxxc+m/2(2c)) = 3/2 T`