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in Physics by (90.2k points)
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50 gram of ice at `0^(@)`C is mixed with 50 gram of water at `60^(@)C` , final temperature of mixture will be :-
A. `0^(@)C`
B. `40^(@)C`
C. `10^(@)C`
D. `15^(@)C`

1 Answer

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by (90.9k points)
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Best answer
Correct Answer - A
Heat liberated when 50 g of water at `60^(@)`C converts into water at `0^(@)`C
Q = ms`DeltaQ`= 50 xx 1 x 60 = 3000 cal
From this heat, mass of ice which can be melted is
`m= Q/L = 3000/80` = 37.5g
i.e, whole ice is not melted and temperature of mixture will be `0^(@)`C.

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