Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.0k views
in Physics by (90.2k points)
closed by
Two rods with the same dimensions have thermal conductivities in the ratio 1 : 2. they are arranged between heat reservoirs with the same temperature difference, in two different configurations, A and B. The rates of heat flow in A and B are `I_(A) and I_(B)` respectively. The ratio `(I_(A))/I_(B))` is equal to
image
A. `1 : 2`
B. `1 : 3`
C. `2 : 5`
D. `2 : 9`

1 Answer

0 votes
by (90.9k points)
selected by
 
Best answer
Correct Answer - D
Rate of heat flow `lalpha(TD)/R`
(H = Temperature difference between two points//R)
As TD = temperature difference is same.
`therefore` I `alpha (1)`/(Thermal resistance)
`I_(A)/I_(B)=R_(B)/R_(A)` = ((R)(2R)//R+2R)/(R+2R) = 2/9`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...