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Three rods of equal length of same material are joined to form an equivalent triangle `ABC` as shown figure. Area of cross-section of rod `AB` is `S` of rod `BC` is `2S` and that of `AC` is `S` , then
image
`{:(,"Column-I",,"Column-II"),((A),"Temperature of junction" B,(p),"Greater than" 50^(@)C),((B),"Heat current in" AB,(q),"Less than" 50^(@)C),((C),"Heat current in BC",(r),"Is equal to current in BC"),(,,(s),"Is " 2/3 "times heat current in AC"),(,,(t),"None"):}`

1 Answer

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Best answer
Correct Answer - A::B::C
Thermal resistance `alpha 1/Area`
image
So let, `R_(BC)` = R
Then `R_(AB) +R_(AC)` = 2R
`H_(1) = H_(2)`
`(100-theta_(B))/R = (theta_(B)-0)/(2R)`
`therefore` `theta_(B) = 66.7^(@)`C
`R_(ABC)`-3R and `R_(AC)`=R
`H_(1) = H_(2) = H_(3)/3`

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