Correct Answer - C
c) As we know that, the rate of cooling is
`(dtheta)/(dt) = bA(theta-theta_(0))`
where, bA=constant
`rArr (dtheta)/(dt) alpha (theta-theta_(0))`
Also `-(dT)/(dt) alpha T-T_(0)`
where, T=temperature and t=time
So, the rate of heat absorbed by cooled body is proportional to `t_(2)-t_(1)`.