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If the rate of emission of radiation by a body at temperature `TK` is `E` then graph between log `E` and log `T` will be .

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If the rate of emission of radiation by a body at temperature `TK` is `E` then graph between log `E` and log `T` will be .
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C. image
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Correct Answer - C
According to Stefan-Boltzmann law, the emissive power is directly proportional to the fourth powerof temperature. So, it will give a straight line.
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