This graph can be of a ball rebounding between two walls situated at position 0 cm and 2 cm . The ball is rebounding from one wall to another, time and again every 2 s with uniform velcoity .
Impulse . Here, velocity = displacement / time = 2 / `100 xx 2` = `0.01 ms^(-1)`
Initial momentum = mu = `0.04 xx 0.01` = `4 xx 10^(-4)` kg `ms^(-1)`
Final momentum = mv = `0.04 xx (-0.01)` = `- 4 xx 10^(-4)` kg `ms^(-1)`
Magnitude of Impulse = Change in momentum
`(4 xx 10^(-4)`) - ( `-4 xx 10^(-4)`) = `8 xx 10^(-4)` kg `ms^(-1)`
Time between two consecutive impulses is 2 s i.e the ball receives an impulse every 2 s.