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+1 vote
5.9k views
in Physics by (214 points)

If the electric field is given by (6i + 3j + 4k) N/c, the flux through a surface of area 20m2 in the Y-Z plane is 

a) 12 units 

b) 120 units 

c) 360 units 

d) 80 units

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1 Answer

+2 votes
by (541 points)

HELLO,

\(\overrightarrow{E}=(6\hat{i}+3\hat{j}+ 4\hat{k})N/C\)

Cross-sectional area = \(20m^2\) 

Surface is in Y-Z plane so its area vector must be along X- axis.

\(\overrightarrow{A}=(20\hat{i})m^2\)

As, we all know that flux is nothing but dot product of Electric field and Area vector.

\(\phi=\overrightarrow{E}\bullet\overrightarrow{A}\)

\(\phi =(6\hat{i}+3\hat{j}+4\hat{k})\bullet(20\hat{i})\)

\(\phi=120\frac{N}{m^2\cdot C}\)

So,Correct option is B.

I HOPE YOU WILL UNDERSTAND.smiley

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