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in Mathematics by (33.1k points)

In the given figure, O is the centre of two concentric circles of radii 5 cm and 3 cm. From an external point p tangents PA and PB are drawn to these circles. If PA = 12 cm then PB is equal to

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by (60.2k points)
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Then, OB = 3 cm 

Now, ∠OAP = 90o (Tangents drawn from an external point are perpendicular to the radius at the point of contract) 

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