An aeroplane is flying horizontally at a height of \( 3464 m \) above the ground. The angle subtended by the aeroplane at a ground observation station, when it moves from \( t_{1}= \) \( 10 s \) to \( t _{2}=20 s \) is \( 30^{\circ} \). What is the speed of the aeroplane? (1) \( 150 m / s \) (2) \( 175 m / s \) (3) \( 200 m / s \) (4) \( 250 m / s \)

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MehulKumar · Answer 1 · 2021-12-03T05:13:26+0000

Slop x x/t = v

v = x/t x tan 30°

v = 3464/(20-70) x tan 30°

v = 3464/10 x 1/√3

v \(=\frac{3464}{10\times1.73}\)

v = 200 m/s