Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
109 views
in Chemistry by (95.5k points)
closed by
`Na_(2)S +Na_(2)[Fe(CN)_(5)NO] to "A" ("Violet Color")`
In Complex "A", number of type of ambidentate ligand is/are "a" and number of d-orbital involved in hybridisation is/are "b" The 7a+8 b will be :

1 Answer

0 votes
by (94.9k points)
selected by
 
Best answer
Correct Answer - 30
`A-=Na_(4)[Fe(CN)_(5)NOS]`
Ambidentate ligand[a] `=CN^(-),NOS^(-)`
a=2
Hybridisation `implies d^(2)sp^(3) implies b=2`
7a+8b=30

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...