Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
72 views
in Chemistry by (95.5k points)
closed by
When compound (A) is treated with conc. `H_(2)SO_(4)`, a reddish brown colour gas (B) is evolved. To this solution, a solution of (C ) is added slowly from the side of the test tube, a blue ring is obtained at the junction of two layers due to formation of (D).

1 Answer

0 votes
by (94.9k points)
selected by
 
Best answer
Correct Answer - C
`underset((A))(NaNO_(3))+H_(2)SO_(4) to NaHSO_(4)+HNO_(3)`
`2HNO_(3) to H_(2)O+ underset((B))(2NO_(2))uarr+[O]`
`2C_(6)H_(5)NHC_(6)H_(5)+[O] to (C_(6)H_(5))_(2)underset("blue ring"(D))(N-N(C_(6)H_(5))_(2))+H_(2)O`
This testing also given by various oxidising agent like `CrO_(4)^(2-), Cr_(2)O_(7)^(2-),ClO_(3)^(-)` etc.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...