Correct Answer - C
`Ag_(3)PO_(4)` is yellow precipitate which is soluble in both dilute ammonia solution and dilute `HNO_(3)`.
`HPO_(4)^(2-)+3Ag^(+) to Ag_(3)PO_(4) darr +H^(+)`
`Ag_(3)PO_(4)+2H^(+) to H_(2)PO_(4^(-)) darr+2Ag^(+)`,
`Ag_(3)PO_(4)darr +6NH_(3) to 3[Ag(NH_(3))_(2)]^(+) +PO_(4)^(3-)`
Pale yellow precipitate of AgBr is not soluble in dilute `HNO_(3)`, bright yellow precipitate of Agl is not soluble in both, `Ag_(2)CrO_(4)` is obtained as red precipitate.