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The rate constant for the decomposition of hydrocarbons is 2.418 × 10−5 s−1 at 546 K. If

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The rate constant for the decomposition of hydrocarbons is 2.418 × 10−5 s−1 at 546 K. If
the energy of activation is 179.9 kJ/mol, what will be the value of pre-exponential factor.

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 k = 2.418 × 10−5 s−1

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