Equation of the tangent is ,
`y = x -11`
Comparing it with `y = mx+c`,
`m = 1`
So, slope of the tangent is `1`.
Now, equation of the curve is,
`y = x^3-11x+5`
`:. 1 = dy/dx = 3x^2-11`
`=>3x^2 -11 = 1`
`=>3x^2 = 12`
`=>x^2 = 4`
`=> x= +-2`
When `x = 2, y = (2)^3-11(2)+5 = -9`
If we put `x = 2, y = -9`, it satisfy the equation, `y = x-11`. So, it is the required point.
When `x = -2, y = (-2)^3-11(-2)+5 = 19`
If we put `x = -2, y = 19`, it does not satisfy the equation, `y = x-11`.
So, the required point on the curve is `(2,-9)`.
