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The molal freezing point constant of water is `1.86 K m^(-1)`. If `342 g` of cane sugar `(C_(12)H_(22)O_(11))` is dissolved in `1000 g` of water, the solution will freeze at
A. `-1.86^(@)C`
B. `1.86^(@)C`
C. `-3.92^(@)C`
D. `2.43^(@)C`

1 Answer

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Best answer
Correct Answer - A
`Delta T_(f)=1.86xx((342)/(342))=1.86^(@)C, therefore T_(f)=-1.86^(@)C`.

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