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The total number of ways in which a beggar can be given atleast one rupee from four 25 paise coins, three 50 paise coins and 2 one rupee coins are

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No. of 25 paise coins = 4 No. of 50 paise coins = 3 No. of 1 rupee coins = 2 Total coins = 9 Total no. of ways to give some or none rupees to a beggar `= (4+1)*(3+1)*(2+1) = 5*4*3 = 60` ways Cases of 0 paisa = 1 Cases of 25 paise = 1 Cases of 50 paise = 2 Cases of 75 paise = 2 Subtracting above cases as they are less than one rupee cases from the total cases: `= 60 - 1 - 1 - 2 - 2 = 54`

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