No. of 25 paise coins = 4
No. of 50 paise coins = 3
No. of 1 rupee coins = 2
Total coins = 9
Total no. of ways to give some or none rupees to a beggar `= (4+1)*(3+1)*(2+1) = 5*4*3 = 60` ways
Cases of 0 paisa = 1
Cases of 25 paise = 1
Cases of 50 paise = 2
Cases of 75 paise = 2
Subtracting above cases as they are less than one rupee cases from the total cases:
`= 60 - 1 - 1 - 2 - 2 = 54`