Question

The base QR of a n equilateral triangle PQR lies on x-axis. The coordinates of the point Q are (-4, 0) and origin is the midpoint of the base. Find the coordinates of the points P and R.

Answer 1

Let (x,0) be the coordinates of R. Then

0 = -4+x/2

x = 4

Thus, the coordinates of R are (4,0).

Here, PQ = QR = PR and the coordinates of P lies on y axis . Let the coordinates of P be (0, y) Then,