Correct Answer - C
`P(V-b)=RT`
`implies PV-Pb=RT implies (PV)/(RT)=(Pv)/(RT)+1`
`implies Z= 1+(PV)/(RT)`
Hence `Z gt 1` at all pressures
This means, repulsive tendencies will be dominant when interatomic distance are small
This means, interatomic potential is never negative but becomes positive at small interatomic distances.
Hence answer is (C ).
`P(V-b)=RT`
`implies PV-Pb= RTimplies (PV)/(RT) =(Pb)/(RT)+1`
`implies Z= 1+(Pb)/(RT)`