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The volume occupied by 8.8 g of `CO_(2)` at `31.1^(@)C` and 1 bar pressure ( in L ) is

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Correct Answer - 5
No of mole of `CO_(2) = (8.8)/(44) = 0.2` mole, `T=304.1K , P =1` bar
`V= (nRT)/(P) = (0.2 xx 0.083 xx 304.1)/(1) = 5L`

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