Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
80 views
in Chemistry by (93.1k points)
closed by
The radioactive decay of `._(35)X^(88)` by a beta emission produces an unstable nucleus which spontaneously emits a neutron. The final product is
A. `.(37)X^(88)`
B. `._(35)Y^(89)`
C. `._(34)Z^(88)`
D. `._(36)W^(87)`

1 Answer

0 votes
by (91.7k points)
selected by
 
Best answer
Correct Answer - D
`._(35)X^(88) overset(-beta)rarr ._(36)W^(88) rarr ._(36)W^(87) + ._(0)n^(1)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...