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75% of the first order reaction was completed in 32 minutes. When was 50% of the reaction completed
A. 24 minutes
B. 16 minutes
C. 8minutes
D. 4 minutes

1 Answer

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Best answer
Correct Answer - B
`N = (25)/(100) N_(0)` (at t = 32 minutes)
Thus, `t = (2.303)/(0.693) xx t_(1//2) "log"(N_(0))/(N)`

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