Question

If a compound on analysis was found to contain `C = 18.5 H = 1.55% ,Cl= 55.04%` and `O = 24.81%`. Then its empirical formula is
A. `CHClO`
B. `CH_(3)ClO`
C. `C_(2)H_(2)Ocl`
D. `ClCH_(2)O`

Answer 1

Correct Answer - A
`{:("Element"," NO. of moles"," Simple ratio"),(C 18.5%,18.5//12=1.54,1),(H1.55%,1.55//1=1.55,1),(Cl55.04%,55.04//35.5=1.55,1),(O24.81%,24.81//16=1.55,1):}`
Hence, formula `= CHClO`.