Correct answer is
(C) 1/4
n(S) = 100
Let A be the event that the number chosen is a prime number.
∴ A = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97}
∴ n(A) = 25
∴ P(A) = \(\frac{n(A)}{n(S)} = \frac{25}{100} = \frac{1}{4}\)