Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
67 views
in Trigonometry by (93.1k points)
closed by
The number of values of `x` in the in interval `[0,5pi]` satisfying the equation `3sin^2x-7sinx+2=0` is 0 (b) 5 (c) 6 (d) 10

1 Answer

0 votes
by (94.2k points)
selected by
 
Best answer
Correct Answer - c
Given , ` " " 3sin ^(2) x - 7 sin x + 2 = 0 `
` rArr 3 sin ^(2) x - 6sin x - sin x + 2 = 0`
` rArr 3 sin x (sinx - 2 ) - 1 ( sinx - 2 ) = 0 `
` rArr " " (3sin x - 1 )(sinx - 2 ) = 0 `
` rArr " " sinx = (1)/(3)" "[because sin x = 2 ` is rejected `]`
` rArr " " x = n pi + (-1) ^(n) sin ^(-1) ""(1)/(3) , n in I `
For ` " " 0 le n le5, x in [0, 5pi]`
There are six values of ` x in [0, 5 pi]` which satisfy the equation ` 3 sin ^(2) x - 7 sin x + 2 = 0 `

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...