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One ball is picked up randomly from a bag containing 8 yellow,7 blue and 6 black balls , what is the probability that it is neither yellow nor black ?
A. `3//4`
B. `4//7`
C. `2//9`
D. `1//3`

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Correct Answer - D
Total no. of balls `=8+7+6=21`
Let ,E be the event where the ball can be selected which is neither yellow nor black
Number of event where the ball can be selected which is neither yellow nor black = 7
`p( E) = 7//21 = 1//3`

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