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0 votes
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in Mathematics by (106k points)

Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?

1 Answer

+1 vote
by (106k points)
 
Best answer

Let Baichung's father's present age be x years
Given Baichung's father is 29 years older than Baichung
Hence Baichung's age is (x − 29) years
Baichung's grandfather is 26 years older than Baichung's father.
Hence Baichung's grandfather's age = (x + 26) years
Given sum of three ages = 135 years
∴ x + (x − 29) +(x + 26) = 135
3x − 3 = 135
3x = 135 + 3  = 138
∴ x = 46
Baichung's father's age = 46 years
Baichung's grandfather's age = (x + 26) = (46 + 26) = 72 years
Baichung's age = (x − 29) = (46 − 29) = 17 years

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