LIVE Course for free

Rated by 1 million+ students
Get app now
JEE MAIN 2023
JEE MAIN 2023 TEST SERIES
NEET 2023 TEST SERIES
NEET 2023
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
158 views
in Biology by (82.2k points)
closed by
A business man of 70 kg weight requires 2800 kcal energy daily. How many glucose molecules and ATP molecules does he require to produce this much energy ?
A. 20 molecules of glucose and 384 molecules of ATP
B. 11 molecules of glucose and 380 molecules of ATP
C. 1 Molecule of glucose and 38 molecules of ATP
D. 6 molecules of glucose and 584 molecules of ATP

1 Answer

0 votes
by (87.7k points)
selected by
 
Best answer
Correct Answer - B
One molecule of glucose yields 686 Kcal of which only 262. 8 Kcal(= 36 ATP) is usable and rest is lost as heat.
1 ATP yields 7.3 Kcal and accordingly (1) number of glucose for 2800 Kcal energy will be`2800/262.8=11`(ii) number of ATP will be `2800/7.3=384`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...