Correct Answer - B
Let `(x-a)^(2)+(y-0)^(2)=r^(2) and x^(2)+(y-b)^(2)=r^(2)`
be two equal circles with their centres on x and y axes respectively. Then, their radical axis is given by
`-2ax+a^(2)+2by-b^(2)=0`
`rArr 2ax-2by+b^(2)-a^(2)=0`
Clearly, is of the form `2gx-2fy+g^(2)-f^(2)=0`.