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`(5xx5xx5xx5xx5xx5)^(4)xx(5xx5)^(6)div(5)^(2)=(25)^(?)`
A. 10
B. 17
C. 19
D. 12

1 Answer

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Correct Answer - B
`(25)^(?)=(5xx5xx5xx5xx5xx5)^(4)xx(5xx5)^(6) div(5)^(2)`
`=(25xx25xx25)^(4) xx(25)^(6)div (25)^(1)`
`=(25^(3))^(4)xx(25)^(6) div 25^(1)=(25)^(12)xx (25)^(6) div (25)^(1)`
`=(25)^(12+6-1)=(25)^(17)`
`:. ?=17`

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