Question

A motorcyclist wants to drive on the vertical surface of a wooden well of radius 5m with a minimum speed of 5√5 The minimum value of coefficient of friction between the tyres and the wall of the well must be?

Answer 1

Frictional force = f = mg

Centripetal Force = Contact force = N = mv² / r

μ = f / N

= mg / (mv² / r)

= rg / v²

= (5 × 10) / (5√5)²

= 50 / 125

= 0.4

Minimum coefficient of friction between the tyres and wall of the well must be 0.4