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The thermal decomposition of formic acid (HCOOH) is a first order reaction with the rate constant of `2.4 xx 10^(-3)s^(-1)` at a certain temperature.Calculate how long will it take for three-fourth of initial quantity of HCOOH to decompose.

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The first order reaction is
`t = (2.303)/(K) log([A]_(0))/([A]_(0))`
where `[A]_(0)= 1 ,[A],([A]_(o))/(4) k = 2.4xx 10^(-5)`
`t= (2.303)/(2.4xx 1^(-3))log. (([A_(o)])/([A_(o)]))/(4) = (2.303)/(2.4xx 10^(-3))log^(4)`
`t=(2.303)/(2.4xx 10^(-3))xx 0.621 = 577 sec`

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