Fewpal
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The coefficients of the (r – 1)th, rth and (r + 1)th terms in the expansion of (x + 1)are in the ratio 1 : 3 : 5. Find n and r.

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Solution: Given the coefficients of( r-1)th, rth and (r+1)th terms in the expansion of (x+1)n are in the ratio 1:3:5

Coefficient of (r-1)th term = C(n, r-2)

Coefficient of rth term = C(n, r-1)

Coefficient of (r+1)th term = C(n, r)

C(n, r-2) : C(n, r-1) : C(n, r) = 1:3:5

Divide 1st and 2nd

C(n,r-2)/C(n,r-1) = 1 / 3

= [n! / (r-2)! (n -r +2)! ] x [(r-1)!(n-r+1)!/ n!] = 1/3


( r -1)(r -2)! / ( r – 2)! ( n -r +2) = 1 / 3

( r -1) / ( n -r +2) = 1 / 3

3r - 3 = n - r + 2

n - 4r = -5 ----------(1)

Divide 2nd and 3rd

C(n,r-1)/C(n,r) = 3/5 

[n! / (r-1)! (n -r +1)! ] x r!(n-r)!/ n! = 3 / 5

r / (n -r + 1) = 3 / 5
 
5r = 3n - 3r +3

3n - 8r = -3 ---------(2)

2(n - 4r = -5)

2n - 8r = -10 ---------(3) 

Subtract (3) from (2)

n = 7

Substitute n = 7 in (2)

We get r = 3

n = 7, r = 3

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