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the equationof a plane is `2x-y-3z=5 and A(1,1,1),B(2,1,-3),C(1,-2,-2) and D(-3,1,2)` are four points. Which of the following line segments are intersects by the plane? (A) AD (B) AB (C) AC (D) BC
A. AD
B. AB
C. AC
D. BC

1 Answer

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Best answer
Correct Answer - B::C::D
For A(1,2,3), 2x-y-5=2-1-5`lt`0
For B(2,1,-3) 2x-y-3z-5=4-1+9-5 `lt` 0
For C(1,-2,-2), 2x-y-3z-5 = 2+2+6-5 `gt` 0
For D(-3,1,2), 2x-y-3z-5 = -6 -1 -6 -5 `lt` 0
`therefore` A,D are on the side of the plane and B,C are on the other side.
`therefore` The line segment AB, AC, BD and CD intersect the plane.

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