Correct Answer - 1,2,3,
` f(x) = Ax^(2) + Bx + C`
` A = a + b - 2c = (a -c) + (b - c) gt 0 `
`rArr A gt 0 `
Hence, the graph is concave upwards. Also, x = 1 is obvious
Solution, therefore .both roots are rational
` b +c - 2a = underset(-ve)underbrace(b - a)+ underset(-ve)underbrace(c - a)lt 0 `
`rArr B lt 0 `
` therefore - (B)/(2A)gt 0 `
Hence , abscissa of the vertex is positive . Option (d) need not be
correct as with a = 5 ,b = 4 , c = 2 , P` lt ` 0 and with a = 6 , b = 3
c = 2, P ` gt ` 0 .