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The first and second term of a G.P. are `x^(-4) and x^(n)` respectively. If `x^(52)` is the `8^(th)` term, then find the value of n.

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Correct Answer - n=4
Given
`r=(T_(2))/(T_(1))=(x^(n))/(x^(-4))=x^(n+4)`
and `T_(8)=ar^(7)=x^(-4)xx(x^(n+4))^(7)=x^(52)` (given)
`rArr7n+24=52`
or n=4

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