Correct Answer - 1728
Let the particular side on which 3 particular sailors can work be named A, and another side B on which 2 particular sailors can work. Thus, we are left with 3 sailors only.
The number of ways of selection of one sailor for side A is `.^(3)C_(1)=3` and then we are left with 2 sailors for other sides. Now, on each side 4 sailors can be arranged in 4! ways. Hence, total number of arrangements is `3xx4!xx4!=3xx24xx24=1728`.