Sarthaks APP
+2 votes
8.5k views
in Mathematics by (65.0k points)
edited by

Find the expansion of (3x2 – 2ax + 3a2)3 using binomial theorem.

1 Answer

+4 votes
by (128k points)
selected by
 
Best answer

Solution:

[3x2a(2x−3a)]3=(3x2)3−3C1(3x2)2.a(2x−3a)+3C2(3x2)a2(2x−3a)2a3(2x−3a)3

⇒27x6−27x4a(2x−3a)+9x2a2(4x2−12ax+9a2)−a3(8x3−3×4×x2×3a+3×2x×9a2−27a3)

⇒27x6−54x5a+81a2x4−108a3x3+81a4x2−8a3x3+36a4x2−54a5x+27a6

⇒27x6−54x5a+117a2x4−116a3x3+117a4x2−54a5x+27a6

Sarthaks APP

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...