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Given: The mass of electron is `9.11 × 10^(–31)`Kg Planck constant is `6.626 ×10^(–34)`Js, the uncertainty involved in the measurement of velocity within a distance of 0.1Å is:-
A. `5.79 × 10^(6)ms(–1)`
B. `5.79 × 10^(7) ms^9–1)`
C. `5.79 × 10^(8) ms^(–1)`
D. `5.79 × 10^(5)ms^(–1)`

1 Answer

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Correct Answer - A
`DeltaxxxDeltavge(h)/(4pim)`
`thereforeDeltax=0.1Å`
` =1xx10^(-11)m`
`Delta V ge(h)/(4pimxxDeltax)` `DeltaVge (6.626xx10^(-34)J sec)/(4xx3.14xx9.11xx10^(-31)kgxx10^(-11)m)` `Delta ge 5.79xx10^(6) m sec^(-1)`

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