Correct Answer - A
For the reaction
`Br_(2)(l)+Cl_(2)(g)to2BeCl(g)`
`DeltaH=30KJ//mol
DeltaS=105jk^(-1)mol^(-1)`
For at equilibrium`DeltaG`=0
`thereforeDeltaG=DeltaH-TDeltaS
DeltaH=TDeltaS`
`T=(DeltaH)/(DeltaS)=(30xx1000J mol^(-1))/(105 JK^(-1))mol^(-1)=285.7k`