Question

1 M solution of `CH_(3)COOH` is diluted to x times so that pH of solution is doubled. Calculate x
Given `K_(a)=1.8xx10^(-5)`

Answer 1

`pH=1/2[pK_(a)-logC]=1/2[pK_(a)-log1]=(pK_(a))/(2)`
`pH=2xxpH=2xx(pK_(a))/(2)=pK_(a)`
`pH=pK_(a)=1/2[pK_(a)-logC]`
`pK_(a)=-logC=-logK_(a)`
`C=K_(a)=1.8xx10^(-5)`
Dilution `x=1/C=0.55xx10^(4)` times