i. 7, -2
If a and b are positive numbers such that a < b, then -a > -b.
Since, 2 < 7 ∴ -2 > -7
ii. 0, \(\cfrac{-9}{5}\)
On a number line, \(\cfrac{-9}{5}\) is to the left of zero.
∴ 0 > \(\cfrac{-9}{5}\)
iii. \(\frac{8}{7}\), 0
On a number line, zero is to the left of \(\cfrac{8}{7}\).
∴ \(\cfrac{8}{7}\) > 0
iv. \(\cfrac{-5}{4}\),\(\cfrac{1}{4}\)
We know that, a negative number is always less than a positive number.
∴ \(\cfrac{-5}{4}\) < \(\cfrac{1}{4}\)
v. \(\cfrac{40}{29}\), \(\cfrac{141}{29}\)
Here, the denominators of the given numbers are the same.
Since, 40 < 141
∴ \(\cfrac{40}{29}\) < \(\cfrac{141}{29}\)
vi. \(\cfrac{-17}{20}\),\(\cfrac{-13}{20}\)
Here, the denominators of the given numbers are the same.
Since, 17 < 13
∴ -17 < -13
∴ \(\cfrac{-17}{20}\) < \(\cfrac{-13}{20}\)
vii. \(\cfrac{15}{12}\), \(\cfrac{7}{16}\)
Here, the denominators of the given numbers are not the same.
LCM of 12 and 16 = 48
Alternate method:
15 × 16 = 240
12 × 7 = 84
Since, 240 > 84
∴ 15 × 16 > 12 × 7
viii. \(\cfrac{-25}{8}\), \(\cfrac{-9}{4}\)
Here, the denominators of the given numbers are not the same.
LCM of 8 and 4 = 8
ix. \(\cfrac{12}{15}\), \(\cfrac{3}{5}\)
Here, the denominators of the given numbers are not the same.
LCM of 15 and 5 = 15
x. \(\cfrac{-7}{11}\), \(\cfrac{-3}{4}\)
Here, the denominators of the given numbers are not the same.
LCM of 11 and 4 = 44
