Question

The equation is followed by the values of the variable. Decide whether these values are the solution of that equation.

2a + 4 = 0, a = 2, – 2, 1

Answer 1

2a + 4 = 0 …..(i)

Substituting a = 2 in L.H.S. of equation (i), 

L.H.S. = 2 (2) + 4 

= 4 + 4 

= 8 

R.H.S. = 0 

∴ L.H.S. ≠ R.H.S. 

∴ a = 2 is not the solution of the given equation.

Substituting a = – 2 in L.H.S. of equation (i), 

L.H.S. = 2 (-2)+ 4 

= -4 + 4 

= 0 

R.H.S. = 0 

∴ L.H.S. = R.H.S. 

∴ a = – 2 is the solution of the given equation.

Substituting a = 1 in L.H.S. of equation (i), 

L.H.S. = 2(1)+ 4 

= 2 + 4 

= 6 

R.H.S. = 0 

∴ L.H.S. ≠ R.H.S. 

∴ a = 1 is not the solution of the given equation.