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एक पाँसा यादृच्छया दो बार फेंका जाता है | प्रत्येक फेक में 3 से बड़ा अंक प्राप्त होने की प्रायिकता ज्ञात कीजिये |

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यदि `E_(1)` पहले फेक में 3 से बड़ा अंक आने की घटना तथा `E_(2)` दूसरी फेक में 3 से बड़ा अंक प्राप्त होने की घटना है | प्रत्येक बार में केवल 3 से बड़ा एक अंक ही ऊपर आयेगा |
`therefore P(E_(1)) = (1)/(2)`
तथा `" " P(E_(2)) = (1)/(2)`
दोनों घटनाएँ स्वतंत्र है | अतः मिक्स प्रायिकता की द्वितीय प्रमेय से,
`P( E_(1) nn E_(2)) = P(E_(1)).P(E_(2))`
`=(1)/(2)xx(1)/(2) = (1)/(4)`

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