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एक अणु के कुछ ऊर्जा-स्तरों को चित्र में दिखाया गया है। तरंगदैर्घ्यों के अनुपात `r=lambda_(1)//lambda_(2)` का मान होगा :
image
A. `r=1//3`
B. `r=4//3`
C. `r=2//3`
D. `r=3//4`

1 Answer

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Correct Answer - A
`-E-(-2E)=("hc")/(lambda_(1))" "…(i)`
`-E-(-(4)/(3)E)=("hc")/(lambda_(2))" "(ii)`
समी० (ii) को (i) से भाग करने पर
`(lambda_(1))/(lambda_(2))=((4)/(3)-1)/(2-1)=(1)/(3).`

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