Correct Answer - B::C
Given, `f_0=50cm` and `f_e=5cm`
For objective `1/v-1/-200=1/50`
`:. v_0=200/3cm`
`m_0=v_0/u_0=((200//3))/(-200)=-(1)/(3)`
For eyepiece `1/-25-1/u_e=1/5`
`:. u_e=-25/6cm`
and `m_e=v_e/u_e=(-25)/-(25//6)=6`
(a) Magnification, `m=m_0xxm_e=-2`
(b) Separation between objective and eyepiece,
`L=v_0+|u_e|=200/3+25/6=425/6`
`=70.83cm`