Question

Chromium metal crystallizes with a body-centred cubic lattice. The length of the unit cell edge is found to be `287`pm. Calculate the atomic radius. What woulds be the density of chromium in `g cm^(-3)`?

Answer 1

For bcc lacttice
`r = (sqrt3)/(4) = (sqrt3 xx 287)/(4) = 124.87 Å`
Density `(rho) = (Z_(eff) xx Mw)/(a^(3) xx N_(A))`
`(2 xx 51.99)/(287 xx 10^(-10))^(3) xx 6.023 xx 10^(23)`
`= 7.30 g cm^(-3)`