Question

The molal freezing point constant of water is `1.86 K m^(-1)`. If `342 g` of cane sugar `(C_(12)H_(22)O_(11))` is dissolved in `1000 g` of water, the solution will freeze at
A. `-1.86^(@)C`
B. `1.86^(@)`
C. `-3.92^(@)C`
D. `2.42^(@)C`

Answer 1

Correct Answer - A
`DeltaT_(f)=(1000 xx K_(f) xx W)/(Mw)`
=`(1000 xx 1.86 xx 342)/(100 xx 342)=1.86`
`:. T_(f) =0-1.86=-1.86^(@)C`