Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
5.0k views
in Mathematics by (30.0k points)

A solid cube of edge 14 cm is melted down and recasted into smaller and equal cubes each of edge 2 cm; find the number of smaller cubes obtained.

1 Answer

+1 vote
by (55.2k points)
selected by
 
Best answer

Edge of the big solid cube = 14 cm

Volume of the big solid cube = 14 x 14 x 14 cm3 = 2744 cm3 

Edge of the small cube = 2 cm

Volume of one small cube = 2 x 2 x 2 cm3 = 8 cm3 

Number of smaller cubes obtained = Volume of big cube/Volume of one small cube = 2744/8 = 343

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...