Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
67 views
in Physics by (91.2k points)
closed by
A certain material has refractive indices 1.56, 1.60 and 1.68 for red, yellow and violet light respectively. (a) Calculate the dispersive power. (b) Find the angular dispersion produced by a thin prism of angle 6° made of this material.

1 Answer

0 votes
by (93.6k points)
selected by
 
Best answer
Correct Answer - A::B
Given that `mu_r=1.56,`
`mu_y=1.60, and mu_c=1.68` a. Dispersive power `=omega`
`=(mu_v-mu_r)/(mu_y-1)=(1.68-1.56)/(1.60-1)`
`=0.12/0.60=0.2`
b. Angular dispersion `=(mu_r-mu_r)a`
`=(0.12)xx6^@=0.72^@`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...